A particle of mass m is moving in a circular path of constant radius r such that its centripetal acceleration a c is varying with time t as a c = k 2 rt 2 , where k is a constant. The power delivered to the particle by the force acting on it is –
A
2п mk 2 r 2
B
mk 2 r 2 t
C
D
Zero
Text Solution
Verified by ExpertsThe correct answer is:
B
a c = k 2 rt 2
or 
= k 2 rt 2 or v = krt
Therefore, tangential acceleration, a t = 
= kr
or Tangential force,
F t = ma t = mkr
Only tangential force does work.
Power = F t v = (mkr) (krt)
or Power = mk
2 r 2 t
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
A body of mass m accelerates uniformly from rest to in time . As a function of time t, the instan…
A man is riding on a cycle with velocity 7.2 km/hr up a hill having a slope 1 in 20. The total mass…
A 12 HP motor has to be operated 8 hours/day. How much will it cost at the rate of 50 paisa/kWh in …
A motor boat is travelling with a speed of 3.0 m/sec. If the force on it due to water flow is 500 N…
An electric motor exerts a force of 40 N on a cable and pulls it by a distance of 30 m in one minut…
An electric motor creates a tension of 4500 newton in a hoisting cable and reels it in at the rate …